9+6x=3x^2

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Solution for 9+6x=3x^2 equation:



9+6x=3x^2
We move all terms to the left:
9+6x-(3x^2)=0
determiningTheFunctionDomain -3x^2+6x+9=0
a = -3; b = 6; c = +9;
Δ = b2-4ac
Δ = 62-4·(-3)·9
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-12}{2*-3}=\frac{-18}{-6} =+3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+12}{2*-3}=\frac{6}{-6} =-1 $

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